Mercurial > vim
view src/testdir/test_exec_while_if.vim @ 30226:b6b803ed4a53 v9.0.0449
patch 9.0.0449: there is no easy way to translate a key code into a string
Commit: https://github.com/vim/vim/commit/cdc839353f68ca43db6446e1b727fc7ba657b738
Author: zeertzjq <zeertzjq@outlook.com>
Date: Mon Sep 12 13:38:41 2022 +0100
patch 9.0.0449: there is no easy way to translate a key code into a string
Problem: There is no easy way to translate a string with a key code into a
readable string.
Solution: Add the keytrans() function. (closes #11114)
author | Bram Moolenaar <Bram@vim.org> |
---|---|
date | Mon, 12 Sep 2022 14:45:04 +0200 |
parents | fb4c30606b4a |
children |
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" Test for :execute, :while, :for and :if func Test_exec_while_if() new let i = 0 while i < 12 let i = i + 1 execute "normal o" . i . "\033" if i % 2 normal Ax if i == 9 break endif if i == 5 continue else let j = 9 while j > 0 execute "normal" j . "a" . j . "\x1b" let j = j - 1 endwhile endif endif if i == 9 execute "normal Az\033" endif endwhile unlet i j call assert_equal(["", \ "1x999999999888888887777777666666555554444333221", \ "2", \ "3x999999999888888887777777666666555554444333221", \ "4", \ "5x", \ "6", \ "7x999999999888888887777777666666555554444333221", \ "8", \ "9x"], getline(1, 10)) endfunc " vim: shiftwidth=2 sts=2 expandtab