Mercurial > vim
view src/testdir/test80.ok @ 5388:8ced827b2e8b v7.4.045
updated for version 7.4.045
Problem: substitute() does not work properly when the pattern starts with
"\ze".
Solution: Detect an empty match. (Christian Brabandt)
author | Bram Moolenaar <bram@vim.org> |
---|---|
date | Sun, 29 Sep 2013 21:11:05 +0200 |
parents | 7faeece39228 |
children | d59544f3022b |
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Results of test72: TEST_1: AA & C123456789987654321 d ~ ~ Gg Hh iI jJ Kk l l m m n n o o pp q q r\r scs u u vv w\w x x YyyY zZZz TEST_2: AA & C123456789987654321 d ~ ~ Gg Hh iI jJ Kk l l m m n n o o pp q q r\r scs t t u u vv w\w XxxX yYYy TEST_3: a\a b\\b c c d\ d e\\ e f\rf j\nj k k l l TEST_4: a\a b\b c c d d e\ e f f j j k k l l TEST_5: A123456789987654321 TEST_6: a % c % TEST_7: A A B B -abab c-cbcbc TEST_8: N,,NX N,,NY N,,NZ TEST_9: XXx