view src/testdir/test80.ok @ 5388:8ced827b2e8b v7.4.045

updated for version 7.4.045 Problem: substitute() does not work properly when the pattern starts with "\ze". Solution: Detect an empty match. (Christian Brabandt)
author Bram Moolenaar <bram@vim.org>
date Sun, 29 Sep 2013 21:11:05 +0200
parents 7faeece39228
children d59544f3022b
line wrap: on
line source

Results of test72:


TEST_1:
AA
&
C123456789987654321
d
~
~
Gg
Hh
iI
jJ
Kk
l
l
m
m
n
n
o
o
pp
q	q
r\r
scs
u
u
vv
w\w
x
x
YyyY
zZZz


TEST_2:
AA
&
C123456789987654321
d
~
~
Gg
Hh
iI
jJ
Kk
l
l
m
m
n
n
o
o
pp
q	q
r\r
scs
t
t
u
u
vv
w\w
XxxX
yYYy


TEST_3:
a\a
b\\b
c
c
d\
d
e\\
e
f\rf
j\nj
k
k
l
l


TEST_4:
a\a
b\b
c
c
d
d
e\
e
f
f
j
j
k
k
l
l


TEST_5:
A123456789987654321


TEST_6:
a
%
c
%


TEST_7:
A
A
B
B
-abab
c-cbcbc


TEST_8:
N,,NX
N,,NY
N,,NZ


TEST_9:
XXx