Mercurial > vim
changeset 5659:ae228baaec2c v7.4.176
updated for version 7.4.176
Problem: Dictionary.update() thows an error when used without arguments.
Python programmers don't expect that.
Solution: Make Dictionary.update() without arguments do nothing. (ZyX)
author | Bram Moolenaar <bram@vim.org> |
---|---|
date | Tue, 11 Feb 2014 18:47:27 +0100 |
parents | 71c900ce7632 |
children | 45f106e69464 |
files | src/if_py_both.h src/testdir/test86.in src/testdir/test87.in src/version.c |
diffstat | 4 files changed, 13 insertions(+), 3 deletions(-) [+] |
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line diff
--- a/src/if_py_both.h +++ b/src/if_py_both.h @@ -1918,11 +1918,17 @@ DictionaryUpdate(DictionaryObject *self, } else { - PyObject *obj; - - if (!PyArg_ParseTuple(args, "O", &obj)) + PyObject *obj = NULL; + + if (!PyArg_ParseTuple(args, "|O", &obj)) return NULL; + if (obj == NULL) + { + Py_INCREF(Py_None); + return Py_None; + } + if (PyObject_HasAttrString(obj, "keys")) return DictionaryUpdate(self, NULL, obj); else
--- a/src/testdir/test86.in +++ b/src/testdir/test86.in @@ -39,6 +39,7 @@ STARTTEST py << EOF d=vim.bindeval('d') d['1']='asd' +d.update() # Must not do anything, including throwing errors d.update(b=[1, 2, f]) d.update((('-1', {'a': 1}),)) d.update({'0': -1})