Mercurial > vim
changeset 25290:8b7ea875afed v8.2.3182
patch 8.2.3182: Vim9: crash when using removing items from a constant list
Commit: https://github.com/vim/vim/commit/885971e2f5eabc4108e083086c1d6d0a31a2782f
Author: Bram Moolenaar <Bram@vim.org>
Date: Sun Jul 18 22:25:29 2021 +0200
patch 8.2.3182: Vim9: crash when using removing items from a constant list
Problem: Vim9: crash when using removing items from a constant list.
(Yegappan Lakshmanan)
Solution: When a list was allocated with items copy them.
author | Bram Moolenaar <Bram@vim.org> |
---|---|
date | Sun, 18 Jul 2021 22:30:03 +0200 |
parents | 82de8cfb8bdc |
children | ef3222de6d9c |
files | src/list.c src/testdir/test_vim9_builtin.vim src/version.c |
diffstat | 3 files changed, 34 insertions(+), 6 deletions(-) [+] |
line wrap: on
line diff
--- a/src/list.c +++ b/src/list.c @@ -1566,12 +1566,32 @@ list_remove(typval_T *argvars, typval_T vimlist_remove(l, item, item2); if (rettv_list_alloc(rettv) == OK) { - l = rettv->vval.v_list; - l->lv_first = item; - l->lv_u.mat.lv_last = item2; - item->li_prev = NULL; - item2->li_next = NULL; - l->lv_len = cnt; + list_T *rl = rettv->vval.v_list; + + if (l->lv_with_items > 0) + { + // need to copy the list items and move the value + while (item != NULL) + { + li = listitem_alloc(); + if (li == NULL) + return; + li->li_tv = item->li_tv; + init_tv(&item->li_tv); + list_append(rl, li); + if (item == item2) + break; + item = item->li_next; + } + } + else + { + rl->lv_first = item; + rl->lv_u.mat.lv_last = item2; + item->li_prev = NULL; + item2->li_next = NULL; + rl->lv_len = cnt; + } } } }
--- a/src/testdir/test_vim9_builtin.vim +++ b/src/testdir/test_vim9_builtin.vim @@ -2083,6 +2083,12 @@ def Test_remote_startserver() CheckDefFailure(['remote_startserver({})'], 'E1013: Argument 1: type mismatch, expected string but got dict<unknown>') enddef +def Test_remove_const_list() + var l: list<number> = [1, 2, 3, 4] + assert_equal([1, 2], remove(l, 0, 1)) + assert_equal([3, 4], l) +enddef + def Test_remove_return_type() var l = remove({one: [1, 2], two: [3, 4]}, 'one') var res = 0